mirror of
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154 lines
3.9 KiB
Go
154 lines
3.9 KiB
Go
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// Loser tree, from https://en.wikipedia.org/wiki/K-way_merge_algorithm#Tournament_Tree
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package loser
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import "golang.org/x/exp/constraints"
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type Value constraints.Ordered
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type Sequence[E Value] interface {
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At() E // Returns the current value.
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Next() bool // Advances and returns true if there is a value at this new position.
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}
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func New[E Value, S Sequence[E]](sequences []S, maxVal E) *Tree[E, S] {
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nSequences := len(sequences)
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t := Tree[E, S]{
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maxVal: maxVal,
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nodes: make([]node[E, S], nSequences*2),
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}
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for i, s := range sequences {
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t.nodes[i+nSequences].items = s
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t.moveNext(i + nSequences) // Must call Next on each item so that At() has a value.
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}
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if nSequences > 0 {
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t.nodes[0].index = -1 // flag to be initialized on first call to Next().
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}
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return &t
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}
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// Call the close function on all sequences that are still open.
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func (t *Tree[E, S]) Close() {
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for _, e := range t.nodes[len(t.nodes)/2 : len(t.nodes)] {
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if e.index == -1 {
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continue
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}
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}
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}
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// A loser tree is a binary tree laid out such that nodes N and N+1 have parent N/2.
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// We store M leaf nodes in positions M...2M-1, and M-1 internal nodes in positions 1..M-1.
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// Node 0 is a special node, containing the winner of the contest.
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type Tree[E Value, S Sequence[E]] struct {
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maxVal E
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nodes []node[E, S]
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}
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type node[E Value, S Sequence[E]] struct {
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index int // This is the loser for all nodes except the 0th, where it is the winner.
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value E // Value copied from the loser node, or winner for node 0.
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items S // Only populated for leaf nodes.
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}
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func (t *Tree[E, S]) moveNext(index int) bool {
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n := &t.nodes[index]
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if n.items.Next() {
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n.value = n.items.At()
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return true
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}
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n.value = t.maxVal
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n.index = -1
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return false
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}
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func (t *Tree[E, S]) Winner() S {
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return t.nodes[t.nodes[0].index].items
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}
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func (t *Tree[E, S]) At() E {
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return t.nodes[0].value
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}
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func (t *Tree[E, S]) Next() bool {
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nodes := t.nodes
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if len(nodes) == 0 {
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return false
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}
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if nodes[0].index == -1 { // If tree has not been initialized yet, do that.
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t.initialize()
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return nodes[nodes[0].index].index != -1
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}
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if nodes[nodes[0].index].index == -1 { // already exhausted
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return false
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}
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t.moveNext(nodes[0].index)
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t.replayGames(nodes[0].index)
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return nodes[nodes[0].index].index != -1
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}
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// Current winner has been advanced independently; fix up the loser tree.
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func (t *Tree[E, S]) Fix(closed bool) {
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nodes := t.nodes
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cur := &nodes[nodes[0].index]
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if closed {
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cur.value = t.maxVal
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cur.index = -1
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} else {
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cur.value = cur.items.At()
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}
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t.replayGames(nodes[0].index)
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}
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func (t *Tree[E, S]) IsEmpty() bool {
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nodes := t.nodes
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if nodes[0].index == -1 { // If tree has not been initialized yet, do that.
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t.initialize()
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}
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return nodes[nodes[0].index].index == -1
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}
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func (t *Tree[E, S]) initialize() {
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winner := t.playGame(1)
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t.nodes[0].index = winner
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t.nodes[0].value = t.nodes[winner].value
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}
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// Find the winner at position pos; if it is a non-leaf node, store the loser.
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// pos must be >= 1 and < len(t.nodes)
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func (t *Tree[E, S]) playGame(pos int) int {
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nodes := t.nodes
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if pos >= len(nodes)/2 {
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return pos
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}
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left := t.playGame(pos * 2)
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right := t.playGame(pos*2 + 1)
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var loser, winner int
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if nodes[left].value < nodes[right].value {
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loser, winner = right, left
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} else {
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loser, winner = left, right
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}
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nodes[pos].index = loser
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nodes[pos].value = nodes[loser].value
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return winner
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}
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// Starting at pos, which is a winner, re-consider all values up to the root.
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func (t *Tree[E, S]) replayGames(pos int) {
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nodes := t.nodes
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winningValue := nodes[pos].value
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for n := parent(pos); n != 0; n = parent(n) {
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node := &nodes[n]
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if node.value < winningValue {
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// Record pos as the loser here, and the old loser is the new winner.
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node.index, pos = pos, node.index
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node.value, winningValue = winningValue, node.value
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}
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}
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// pos is now the winner; store it in node 0.
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nodes[0].index = pos
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nodes[0].value = winningValue
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}
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func parent(i int) int { return i >> 1 }
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